factor polynomial using difference or sum of cubes
64x^6 - h^6
please with baby steps
thank you!
64x^6 - h^6
= (4x^2)^3 - (h^2)^3
= (4x^2-h^2)((4x)^2+(4x)(h^2)+(h^2)^2) = ...
note that 4x^2-h^2 can also be factored as the difference of squares.