solve the equation 3x-y=3,9x-y=45
It a good solving but is not all that is solved
Multiply first equation by 3.
9x - 3y = 9
9x - y = 45
Subtract the second equation from the first to find y. Insert that value into either equation to find x.
Solv d equ
3x-y=3
9xsqu-ysqu=45
To solve the given system of equations:
Step 1: Elimination method
First, let's cancel out the y-term in the equations by subtracting the second equation from the first equation.
(3x - y) - (9x - y) = (3 - 45)
This simplifies to:
-6x = -42
Step 2: Solve for x
To isolate the variable x, divide both sides of the equation by -6.
-6x / -6 = -42 / -6
x = 7
Step 3: Substitute x into one of the original equations
Using the first equation, substitute x = 7.
3(7) - y = 3
21 - y = 3
Step 4: Solve for y
Subtract 21 from both sides of the equation to isolate y.
21 - 21 - y = 3 - 21
-y = -18
Multiply both sides of the equation by -1 to get y by itself.
y = 18
Step 5: Solution
The solution to the system of equations is x = 7 and y = 18.
Therefore, the values of x and y that satisfy the given equations are x = 7 and y = 18.