Math

if (3-a) 6(2-5a) are conservative terms of a GP with common ratio r>0.
find the value of a

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asked by Kamara
  1. I will assume you meant to say:
    3-a , 6, and 2-5a are consecutive terms of a GP,

    (3-a)(2-5a) = 36
    6 -17a + 5a^2 - 36 = 0
    5a^2 - 17a - 30 = 0
    a = (17 ± √889)/10

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