Check these please:
e=6 r=-9 y=5
er:3 +2y
6(-9) :3 +2(5)
-54 :3 +10
-18 + 10 = -8
(y + r )^2
5 +-9 x2
14x14=196
#1 ok, though fractions are usually written using a / instead of a :
(y+r)^2 = (5-9)^2 = (-4)^2 = 16
you did (y-r)^2
avoid using x as an operator; it's too easy to confuse it with a variable.
r=-9
e=6
t=4/5
re/t=
-9 x 6/4/5=54 x4/5=54x5/4=67.5
check this I think this is ri
Let's evaluate the first expression: er:3 + 2y.
To calculate this expression, we substitute the values of e, r, and y into the equation.
e = 6, r = -9, and y = 5.
So the expression becomes:
6(-9) : 3 + 2(5).
Next, we perform the multiplication and division, following the order of operations (PEMDAS/BODMAS).
6(-9) = -54.
2(5) = 10.
Now, the expression is:
-54 : 3 + 10.
Dividing -54 by 3 gives us -18.
Finally, we add -18 + 10 to get -8.
Therefore, the value of the expression er:3 + 2y is -8.
Moving on to the second expression: (y + r)^2.
We have y = 5 and r = -9.
So, (5 + -9)^2 becomes (-4)^2.
To evaluate (-4)^2, we square the value, which simply means multiplying it by itself.
(-4)^2 = (-4) x (-4) = 16.
Hence, the value of the expression (y + r)^2 is 16.
In summary:
- er:3 + 2y = -8
- (y + r)^2 = 16