write an equation in point slope form for the line through the given point with the given slope.

(-3,5); m=2/3

I don't understand how to figure this out

ok there are also answer choices

A. y+3= 2/3(x-5)
B. y+5=(2/3)(x+3)
C. y-5=2/3(x-3)
D. y-5=2/3(x+3)

it's D. took the exam

Point slope form is in the format y = mx + b, where m is your slope (in this case 2/3) and your x and y values can be that of any point on the line (in this case we have (x,y) = (-3,5)). Plug these values into the above format and use algebra to solve for b, your y intercept. Once you have done so, you can simply write your final answer without plugging in anything for x and y since they are their variables. Basically, the ultimate goal here is to find b (your y intercept) and m, which is already given to you.

Well, let me shed some light on that for you! Don't worry, it's not as complicated as it may seem.

To write an equation in point-slope form, we need the coordinates of a point on the line (in this case, (-3,5)) and the slope of the line (m = 2/3).

The point-slope form of a linear equation is given by:

y - y₁ = m(x - x₁)

Where (x₁, y₁) represents the coordinates of the given point, and m represents the slope of the line.

Now, let's plug in the values we have:

y - 5 = (2/3)(x - (-3))

Simplifying the equation leads us to:

y - 5 = (2/3)(x + 3)

And there you have it! The equation in point-slope form for the line through the point (-3,5) with a slope of 2/3 is y - 5 = (2/3)(x + 3).

Remember, math can be fun, even if it seems a bit puzzling at first!

To write an equation in point-slope form, you need two pieces of information: the coordinates of a point on the line and the slope of the line. In this case, you are given the point (-3, 5) and the slope m = 2/3.

The point-slope form of an equation is given by:
y - y₁ = m(x - x₁)

Where (x₁, y₁) represents a point on the line, and m is the slope.

Now let's substitute the given values into the equation:

Let (x₁, y₁) = (-3, 5) and m = 2/3:

y - 5 = (2/3)(x - (-3))

Simplifying:

y - 5 = (2/3)(x + 3)

Distribute 2/3 to (x + 3):

y - 5 = (2/3)x + 6/3

Simplify 6/3 to 2:

y - 5 = (2/3)x + 2

This is the equation in point-slope form for the given line.

you are given a point and a slope.

So, just use the point-slope form!
y-5 = 2/3 (x+3)
Looks like you have some reviewing to do.