How many grams of NaC2H3O2 (M=82.034 g mol-1) should be dissolved in 400 g of water to prepare a solution which is 11.28% NaC2H3O2 by mass?
[Mass of salt/(mass salt + 400)]*100 = 11.28
Solve for mass salt. The easiest way is to let mass salt = x where ever mass salt appears and solve for x.
I obtained an answer close to 50 grams. Post your work if you get stuck.
To determine the number of grams of NaC2H3O2 needed to prepare the solution, we can use the equation:
% mass of solute = (mass of solute / mass of solution) x 100%
In this case, we are given that the solution is 11.28% NaC2H3O2 by mass and the mass of the solution is 400 g.
Let's calculate the mass of NaC2H3O2 using the given information:
% mass of NaC2H3O2 = (mass of NaC2H3O2 / mass of solution) x 100%
11.28% = (mass of NaC2H3O2 / 400 g) x 100%
Rearranging the equation to solve for the mass of NaC2H3O2:
mass of NaC2H3O2 = (11.28% / 100%) x 400 g
mass of NaC2H3O2 = (0.1128) x 400 g
mass of NaC2H3O2 = 45.12 g
Therefore, you should dissolve 45.12 grams of NaC2H3O2 in 400 grams of water to prepare the desired solution.