Chlorous acid reacts with ammonium chromate. How do I balance this?
Will you please provide the products of the reaction; i.e., the equation your are trying to balance?
HClO2 + (NH4)2CrO4 ==>
To balance the equation for the reaction between chlorous acid (HClO2) and ammonium chromate ((NH4)2CrO4), follow these steps:
Step 1: Write the unbalanced equation:
HClO2 + (NH4)2CrO4 → H2CrO4 + NH4ClO2
Step 2: Balance the atoms other than hydrogen and oxygen:
HClO2 + (NH4)2CrO4 → H2CrO4 + NH4ClO2
The chromium (Cr) atoms are already balanced, as there is one on each side.
Next, let's balance the nitrogen (N) atoms. There are two ammonium ions [(NH4)+] on the left side, so we need two ammonium chloride (NH4Cl) molecules on the right side:
HClO2 + (NH4)2CrO4 → H2CrO4 + 2NH4ClO2
Now, let's balance the chlorine (Cl) atoms. There is one chloride ion (Cl-) in each ammonium chlorate (NH4ClO2) molecule on the right side. To balance the chlorine atoms, we need two chloric acid (HClO3) molecules on the left side:
2HClO2 + (NH4)2CrO4 → H2CrO4 + 2NH4ClO2
Finally, let's balance the hydrogen (H) and oxygen (O) atoms. There are two hydrogen atoms and four oxygen atoms on each side:
2HClO2 + (NH4)2CrO4 → H2CrO4 + 2NH4ClO2
Now, the equation is balanced, with two chlorous acid (HClO2) molecules reacting with one ammonium chromate ((NH4)2CrO4) to produce one chromic acid (H2CrO4) and two ammonium chlorate (NH4ClO2) molecules.
To balance the equation for the reaction between chlorous acid (HClO2) and ammonium chromate (NH4)2CrO4), follow these steps:
Step 1: Write the unbalanced equation:
HClO2 + (NH4)2CrO4 →
Step 2: Count the number of atoms on each side of the equation:
Left side: 1 hydrogen (H), 1 chlorine (Cl), 2 oxygen (O), 2 nitrogen (N), and 4 hydrogen (H)
Right side: 2 nitrogen (N), 4 hydrogen (H), 1 chromium (Cr), 4 oxygen (O)
Step 3: Balance the non-hydrogen and non-oxygen atoms first:
Since there are two nitrogens (N) on the right side and only one on the left side, place a coefficient of 2 in front of HClO2:
2 HClO2 + (NH4)2CrO4 →
Now, the equation looks like this:
2 HClO2 + (NH4)2CrO4 →
Step 4: Balance the hydrogen atoms next:
On the right side, there are four hydrogen (H) atoms, so we need to balance that on the left side by placing a coefficient of 4 in front of HClO2:
4 HClO2 + (NH4)2CrO4 →
Now, the equation looks like this:
4 HClO2 + (NH4)2CrO4 →
Step 5: Balance the chlorine atoms:
On the left side, there are four chlorine (Cl) atoms, so we need to balance that on the right side by placing a coefficient of 4 in front of NH4:
4 HClO2 + 4(NH4)2CrO4 →
Now, the equation looks like this:
4 HClO2 + 4(NH4)2CrO4 →
Step 6: Finally, balance the oxygen atoms:
On the left side, there are eight oxygen (O) atoms, so we need to balance that on the right side by placing a coefficient of 4 in front of (NH4)2CrO4:
4 HClO2 + 4(NH4)2CrO4 →
Now, the equation is balanced:
4 HClO2 + 4(NH4)2CrO4 → 4 NH3 + 2 Cr2O3 + 6 H2O + 4 H2O + 4 ClO2
The balanced equation for the reaction between chlorous acid and ammonium chromate is:
4 HClO2 + 4(NH4)2CrO4 → 4 NH3 + 2 Cr2O3 + 6 H2O + 4 ClO2