Without looking, George pulls socks from a drawer containing 2 white socks, 3 black socks, and 5 yellow socks. With each pulll, a sock is removed from the drawer and is not replaced. find the probability of drawing a yellow, black, and white sock in that order.
original 10 socks
first pull 5/10 = 1/2
now 9 socks, 2 w + 3 b + 4 y
second pull 3/9 = 1/3
now 8 socks 2 w + 2 b + 4 y
third pull
2/8 = 1/4
final
1/2 * 1/3 * 1/4 = 1/24
not likely :)
To find the probability of drawing a yellow, black, and white sock in that specific order, we need to calculate the probability of each event occurring in sequence.
First, let's find the probability of drawing a yellow sock. George has a total of 2 + 3 + 5 = 10 socks in the drawer, with 5 of them being yellow. Therefore, the probability of drawing a yellow sock on the first pull is 5/10.
Once George has removed one sock, there are now a total of 9 socks left in the drawer. Out of these socks, there are 2 white socks and 3 black socks. Therefore, the probability of drawing a black sock on the second pull is 3/9.
After the second sock is removed, there are now a total of 8 socks remaining, with 2 white socks and 2 black socks. Thus, the probability of drawing a white sock on the third pull is 2/8.
To find the overall probability of this sequence of events happening, we multiply the probabilities of each event occurring in sequence:
(5/10) * (3/9) * (2/8) = 1/12
Therefore, the probability of drawing a yellow, black, and white sock in that specific order is 1/12.