Twice the difference of a number and 3 is at most 28.
The difference of twice a number and 7 is greater than 28.
To solve this problem, we need to translate the given statement into an equation.
Let's assume the number is represented by the variable "x".
"Twice the difference of a number and 3" can be expressed as 2(x - 3).
The given statement "is at most 28" can be translated as the inequality 2(x - 3) ≤ 28.
To solve this inequality, we need to isolate the variable "x":
2(x - 3) ≤ 28
2x - 6 ≤ 28 (distribute 2)
2x ≤ 34 (add 6 to both sides)
Now, divide both sides by 2:
x ≤ 34/2
x ≤ 17
So, the value of the number should be less than or equal to 17, based on the given inequality.
To solve this problem, we need to set up an inequality equation.
Let's assume the number is 'x'. Twice the difference of a number and 3 can be expressed as:
2(x - 3)
According to the problem, this expression is at most 28. So we can write the inequality as:
2(x - 3) ≤ 28
To solve this inequality, we can begin by dividing both sides by 2:
(x - 3) ≤ 14
Next, we can add 3 to both sides to isolate 'x':
x - 3 + 3 ≤ 14 + 3
x ≤ 17
This means that any value of 'x' that is less than or equal to 17 will satisfy the inequality given in the problem.