Consider a .900 M Al(NO3)3 solution. This solution has a nitrate ion concentration of:
There are three nitrates per molecule, so
M=3*basicmolecularConcentrationGiven
2.7M
To find the nitrate ion concentration in a 0.900 M Al(NO3)3 solution, we need to consider the dissociation of the compound.
Al(NO3)3 dissociates into aluminum cations (Al3+) and nitrate anions (NO3-). The compound Al(NO3)3 contains three nitrate ions for each molecule.
So, for every 1 mole of Al(NO3)3, we have 3 moles of nitrate ions.
In a 0.900 M Al(NO3)3 solution, the concentration of the aluminum cations and nitrate anions is the same. Therefore, the nitrate ion concentration is also 0.900 M.
Hence, the nitrate ion concentration in a 0.900 M Al(NO3)3 solution is 0.900 M.