A women is now 3 times as old as his son.In 10 years times , the sum of their ages will be 76. How old was the woman when her son was born ?
W = Women´s present age
S = Son´s present age
A women is now 3 times as old as his son means:
W = 3 S
After 10 yrs women will be W + 10 yrs old, son wil bee S + 10 yrs old.
In 10 years times, the sum of their ages will be 76 means:
W + 10 + S + 10 = 76
Replace W = 3 S in this equation:
3 S + 10 + S + 10 = 76
4 S + 20 = 76
Subtract 20 to both sides
4 S = 56
Divide both sides by 4
S = 14
Son´s present age = 14
W = 3 S = 3 * 14 = 42
Woman´s present age = 42
When her son was born woman was 42 - 14 = 28 yrs old
Well, it seems like there's a little mix-up with the pronouns here. Let's assume you meant to say "A woman is now 3 times as old as her son." Us humans tend to mix things up sometimes, just like mixing up sugar and salt in a recipe!
Now, let's solve the problem.
Let's say the son's current age is "x" years. So, the woman's current age would be 3 times that, which is 3x years.
In 10 years, the son's age will be x+10 years, and the woman's age will be 3x+10 years.
According to the problem, in 10 years' time, the sum of their ages will be 76. So, we can write an equation: (x+10) + (3x+10) = 76.
Simplifying that equation, we get 4x + 20 = 76.
Now, to solve for x, we subtract 20 from both sides: 4x = 56.
Dividing both sides by 4, we get x = 14.
So, the son's current age is 14 years.
Now, let's find out how old the woman was when her son was born. Well, if her son is currently 14, and let's assume the son was born x years ago, then the woman's age at that time would have been 3x.
So, the woman was 3x years old when her son was born - which means she was 3(14) = 42 years old when her son was born.
So, the woman was 42 years old when her son was born. Time sure flies, doesn't it?
Let's assume the current age of the son is "x" years.
According to the information given, the woman is currently 3 times as old as her son.
So, the current age of the woman would be 3x years.
In 10 years, the age of the son will be x + 10 years.
The age of the woman in 10 years will be 3x + 10 years.
According to the given information, the sum of their ages in 10 years will be 76.
So, (x + 10) + (3x + 10) = 76.
Simplifying the equation:
4x + 20 = 76.
Subtracting 20 from both sides:
4x = 56.
Dividing both sides of the equation by 4:
x = 14.
Hence, the current age of the son is 14 years.
To find the age of the woman when her son was born, we need to subtract 14 years from the current age of the woman.
Therefore, the woman was 3x - x = 2x = 2 * 14 = 28 years old when her son was born.
Excellent, I have tried this using bizarre methods. This explanation is straight and simple. Thanks
To find the age of the woman when her son was born, we first need to determine the current ages of the woman and her son. Let's denote the current age of the son as x.
According to the given information, the woman is now 3 times as old as her son, which means her current age is 3x.
In 10 years, the sum of their ages will be 76. This means that the son's age will be x + 10, and the woman's age will be 3x + 10.
We can now form an equation based on the given information:
(x + 10) + (3x + 10) = 76
Simplifying the equation:
4x + 20 = 76
4x = 56
x = 14
So, the current age of the son is 14, and the current age of the woman is 3 * 14 = 42.
To find the age of the woman when her son was born, we need to subtract the son's current age from the woman's current age:
42 - 14 = 28
Therefore, the woman was 28 years old when her son was born.