Suppose you have 12 coins that total 32 cents. Some of the coins are nickels and the rest are pennies. How many of each coin do you have?
p + n = 12 this represents the number of pennies and nickels.
.01 p + .05 n = .32 in this equation, you are getting the value of the coins.
The problem may be easier if you multiply the 2nd equation by 100
p + 5n = 32. finally use elimination to fine p and n by using the first equation and this equation. Hope that helps. Remember to check your answer to be sure that the number of coins adds to 12 and the value of the coins = 32 cents.
5 nickles. 7 penny's
To solve this problem, we can set up a system of equations based on the given information.
Let's say the number of nickels = N
And the number of pennies = P
We can write two equations based on the given information:
1. N + P = 12 (Equation 1: The total number of coins is 12)
2. 5N + 1P = 32 (Equation 2: The total value of the coins in cents is 32 cents)
Now we can use this system of equations to find the values of N and P.
To solve the system of equations, we can use substitution or elimination method.
Using the substitution method:
From Equation 1, we can rewrite it as P = 12 - N.
Now we substitute this value of P in Equation 2:
5N + 1(12 - N) = 32
5N + 12 - N = 32
4N + 12 = 32
4N = 32 - 12
4N = 20
N = 20/4
N = 5
Now we substitute the value of N in Equation 1 to find P:
5 + P = 12
P = 12 - 5
P = 7
So, there are 5 nickels and 7 pennies.
Therefore, the solution is that there are 5 nickels and 7 pennies among the 12 coins that total 32 cents.
add up the coins, and add up the values.
Now solve those two equations.
What do you get?