Find the following indefinite integrals.
∫(cos(t)) / (9sin(t)+10)^(2) dt
let u = 9sint+10
then du = 9cost, and so cost = 1/9 du
So, your integral becomes
∫ 1/9 du/u^2
∫(cos(t)) / (9sin(t)+10)^(2) dt
then du = 9cost, and so cost = 1/9 du
So, your integral becomes
∫ 1/9 du/u^2