The owner of the Good Deals Store opens a new store across town. For the new store, the owner estimates that, during business hours, an average of 90 shoppers per hour enter the store and each of them stays an average of 12 minutes. The average number of shoppers in the new store at any time is what percent less than the average number of shoppers in the original store at any time?
Unless I assume that half his former customers go to the new store and still stay the same time I do not have enough information. If so then 50%
To find the percentage difference, we first need to determine the average number of shoppers in the new store at any time.
Step 1: Convert the average number of shoppers per hour to the average number of shoppers per minute.
To do this, divide the average number of shoppers per hour by 60 (the number of minutes in an hour).
90 shoppers per hour ÷ 60 minutes = 1.5 shoppers per minute.
Step 2: Multiply the average number of shoppers per minute by the average amount of time spent in the store.
1.5 shoppers per minute × 12 minutes = 18 shoppers.
Therefore, the average number of shoppers in the new store at any time is 18.
Now, let's compare this to the original store.
To determine the percentage less, we need to find the difference between the two values and express it as a percentage of the original value.
Step 3: Calculate the difference between the average numbers of shoppers in the original and new stores.
Original store: Assume there are x shoppers on average at any time.
Difference = x - 18.
Step 4: Express the difference as a percentage of the original value.
Percentage Difference = (Difference/original value) × 100.
Percentage Difference = (x - 18)/x × 100.
So, the average number of shoppers in the new store at any time is (x - 18)/x × 100 percent less than the average number of shoppers in the original store at any time.