A closed organ pipe has a length of 0.30 meters. What will be the wavelength of the fundamental wavelength of sound produced by this closed pipe?
If it is closed on both ends you have a node on each end and half a wavelength fits in perfectly so lambda = 2 * 0.30 = 0.60
If it were closed on one end and open on the other then you would have a node on the closed end and big noise on the open end. 1/4 wave fits in. Then Lambda would be 4 * Length
To find the wavelength of the fundamental wavelength of sound produced by a closed organ pipe, you can use the formula:
λ = 4L
where λ is the wavelength and L is the length of the pipe.
Given that the length of the closed organ pipe is 0.30 meters, we can substitute this value into the formula:
λ = 4(0.30)
Calculating this, we get:
λ = 1.20 meters
Therefore, the wavelength of the fundamental wavelength of sound produced by the closed pipe is 1.20 meters.
To find the wavelength of the fundamental frequency of sound produced by a closed organ pipe, you can use the formula:
λ = 4L
where λ is the wavelength and L is the length of the pipe.
In this case, the length (L) of the closed organ pipe is given as 0.30 meters.
Simply substitute the given value into the formula:
λ = 4 * 0.30
λ = 1.20 meters
Therefore, the wavelength of the fundamental frequency of sound produced by the closed pipe is 1.20 meters.