Four kids; Aaron, Bessy, Carli, and Dawn Play with beads. They start with 200 beads in all. Aaron gave Bessy 26 beats, Bessy gave Carli 36 beats, Carli gave Dawn 32 beads, and Dawn gave Aaron 4 beads. They end up with the same number of beads each other. How many beads did each of them have at the beginning?
Aaron has A - 26 + 4 = A - 22
Bessy has B + 26 - 36 = B -10
Carli has C +36 -32 = C + 4
Dawn has D +32 -4 = D + 28
A + B + C + D = 200 at start and at finish
A-22 = B - 10 = C+4 = D+28 = 200/4 = 50
so
A = 50 + 22
B = 50 + 10
C = 50 - 4
D = 50 - 28
luckily 22+10 - 2 - 28 is zero :)
would it be 50 beads each
dont know if i'm right though
what are the answer choices
No answer choices, free answer sort of thing.
no nunya
A = 72
B = 60
C = 46
D = 22
You just literally blew my mind! The answer is 0 then? Iām so stupid š
No, the sum of changes is 0
the answer is
A = 72
B = 60
C = 46
D = 22