What is the line of symmetry of the function
x^2 - 2x + 8 ???
Half way between the zeros is the line of symmetry.
So factor the function and find the zeros : )
To find the line of symmetry of a function, you need to find the x-coordinate of the vertex. The vertex is the point on the graph where the function reaches its minimum or maximum value, and the line of symmetry is a vertical line that passes through the vertex.
The equation of the line of symmetry can be found using the formula: x = -b / (2a), where a and b are the coefficients of the quadratic function in the form of ax^2 + bx + c.
For the given function x^2 - 2x + 8, the coefficient of x^2 (a) is 1 and the coefficient of x (b) is -2.
Using the formula, we can calculate the x-coordinate of the vertex:
x = -(-2) / (2*1)
x = 2 / 2
x = 1
Therefore, the line of symmetry for the function x^2 - 2x + 8 is x = 1.
To find the line of symmetry of a function, you can use the formula x = -b/2a, where the quadratic function is in the form ax^2 + bx + c.
In this case, the function is x^2 - 2x + 8.
Comparing this function with the standard form, we can see that a = 1, b = -2, and c = 8.
We can substitute these values into the formula:
x = -(-2) / (2 * 1)
Simplifying the expression:
x = 2 / 2
x = 1
So, the line of symmetry for the function x^2 - 2x + 8 is x = 1.