Two movers are pushing a large crate. One pushes n with a force of 40.0 n, and the other pushes east with a force of 35.0 n. What force must a third mover exert to keep the crate in equilibrium?
what is the resultant of the two forces?
The third force must be the same magnitude, but the opposite direction.
To keep the crate in equilibrium, the net force acting on the crate should be zero. This means that the combined force exerted by the two movers should be balanced by the force exerted by the third mover.
In this case, one mover is pushing with a force of 40.0 N, and another mover is pushing with a force of 35.0 N. Since the first mover is pushing vertically (north), we can label this force as "Fn = 40.0 N". The second mover is pushing horizontally (east), so we can label this force as "Fe = 35.0 N".
Now, we can break down these forces into their components. Since the forces are at right angles to each other, we can use the Pythagorean theorem to calculate the net force:
Net force (Fnet) = sqrt(Fn^2 + Fe^2)
Plugging in the values, we have:
Fnet = sqrt((40.0 N)^2 + (35.0 N)^2)
Fnet = sqrt(1600 N^2 + 1225 N^2)
Fnet ≈ sqrt(2825 N^2)
Fnet ≈ 53.14 N
Therefore, the third mover must exert a force of approximately 53.14 N to keep the crate in equilibrium.