nine times the sum of a number and 26 is at most -23
the sum of a number and 26 : n+26
nine times : 9*
so, what do you think is next?
What is three times the sum of a number an 23is at most -17
To solve this inequality, let's assign a variable to the unknown number. Let's call the unknown number "x".
The problem states:
"Nine times the sum of a number and 26 is at most -23."
To translate this into an inequality, we can write:
9(x + 26) ≤ -23
Now, let's solve this inequality step-by-step:
1. Distribute the 9 to each term inside the parentheses:
9x + 9(26) ≤ -23
2. Simplify the expression inside the parentheses:
9x + 234 ≤ -23
3. Subtract 234 from both sides to isolate the variable term:
9x ≤ -23 - 234
Simplifying further:
9x ≤ -257
4. Divide both sides of the inequality by 9 to solve for x:
(9x)/9 ≤ (-257)/9
Simplifying:
x ≤ -257/9
So, the solution to the inequality is x ≤ -257/9.
To solve this problem, we can break it down into steps:
Step 1: Let's assume the number is represented by the variable "x".
Step 2: The sum of a number (x) and 26 is x + 26.
Step 3: Multiply the sum by 9: 9(x + 26).
Step 4: Set up the inequality: 9(x + 26) ≤ -23.
Step 5: Simplify the inequality: 9x + 234 ≤ -23.
Step 6: Move the constant term to the other side of the inequality: 9x ≤ -23 - 234.
Step 7: Simplify: 9x ≤ -257.
Step 8: Divide both sides of the inequality by 9 to solve for x: x ≤ -257/9.
Therefore, the solution for the original problem is x ≤ -257/9, which means the number x is at most -257/9.