What is the x intercepts of
f(x) = (x +1)squared (x-2) (x-3)
Is it (-1,0), (2,0), (3,0),(-1,0) ?
Or is it only (-1,0), (2,0) and (3,0)
Thank you
Ah, I think you just divided by zero :)
Only the three. If it just grazes the x axis, that only counts as one intercept.
F(x) = (x+1)^2(x-2)(x-3) = 0.
x-2 = 0. (2, 0).
x-3 = 0. (3, 0).
(x+1)^2 = 0.
Divide both sides by x+1:
x+1 = 0. (-1, 0).
To find the x-intercepts of a function, you need to determine the values of x for which the function equals zero. In this case, the function is given by f(x) = (x + 1)^2 (x - 2) (x - 3).
To find the x-intercepts, set the function equal to zero and solve for x:
0 = (x + 1)^2 (x - 2) (x - 3)
Since the product of several factors equals zero if and only if at least one of the factors equals zero, we can set each factor equal to zero and solve for x:
1) x + 1 = 0
Solving for x, we get x = -1.
2) x - 2 = 0
Solving for x, we get x = 2.
3) x - 3 = 0
Solving for x, we get x = 3.
Therefore, the x-intercepts of the function f(x) = (x + 1)^2 (x - 2) (x - 3) are x = -1, x = 2, and x = 3. So both (-1, 0), (2, 0), and (3, 0) are correct answers.