Ojoe is holding his kite string 3 feet above the ground . The distance between his hand and a point directly under the kite is 95 feet . If the angle of elevation to the kite is 50 , find the height of his kite , h , to the nearest foot
h = 3 + [95 * tan(50)]
this is for me to solve correct ?
To find the height of Ojoe's kite, we can use trigonometry. In this case, we have a right triangle formed by Ojoe, the ground, and the point directly under the kite.
Let's label the sides of the triangle:
- The side opposite to the angle of elevation (50 degrees) is the height of the kite (h).
- The side adjacent to the angle of elevation is the distance between Ojoe's hand and the point directly under the kite (95 feet).
- The side opposite to the right angle is the distance between Ojoe's hand and the ground (3 feet).
We can use the tangent function (tan) to relate the angle of elevation (50 degrees) to the height of the kite (h) and the adjacent side (95 feet).
tan(50 degrees) = h / 95
To find h, we can rearrange the equation:
h = tan(50 degrees) * 95
Using a scientific calculator or a trigonometric table, we can find the tangent value for 50 degrees (approximately 1.1918). Plugging in this value, we get:
h ≈ 1.1918 * 95
h ≈ 113.22
Therefore, the height of Ojoe's kite is approximately 113 feet.