3(y-1)=2x+2
I need to find the slope and I am not sure how to with this equation?
3(y-1) = 2x + 2.
3(y-1) = 2(x+1),
y-1 = ( 2/3)(x+1). Point-slope form.
m = 2/3.
Yay i understand now!!!!!! Thank you so much
Glad I could help.
To find the slope of the equation 3(y-1) = 2x+2, we need to rewrite it in slope-intercept form, which is y = mx + b. In this form, the coefficient of x represents the slope of the line.
Let's start by simplifying the equation:
3(y-1) = 2x+2
Expand the left side:
3y - 3 = 2x + 2
Rearrange the equation to isolate y:
3y = 2x + 5
Divide every term by 3:
y = (2/3)x + 5/3
Now the equation is in slope-intercept form, y = mx + b, where m represents the slope. In this case, the slope is 2/3.
Therefore, the slope of the equation 3(y-1) = 2x+2 is 2/3.