If Goldberg is delivering presents at an altitude of 5,813.6ft, with the same drag and weight of a 2019 Challenger SRT® Hellcat Redeye, how much HP would he need to reach 400 mph?

Pro Tips

•100% driveline efficiency
•P (air density) at 5813.6 ft = .0019 slug/ft^3
•A (Area of Challenger front end) = 26.72 ft^2
•C(d) (Coefficient of drag) = .398
•Goldberg's sleigh required speed, 400 MPH = 587 ft/sec
•F(drag) = 1/2 p x v^2 x C(d)A
•P = F(drag) x V
•Convert to Horsepower = P ( 1HP/550 ft lbf/sec)

3715 hp

To calculate the horsepower (HP) that Goldberg would need to reach 400 mph while delivering presents at an altitude of 5,813.6 ft, we can use the following formula:

F(drag) = 1/2 * p * v^2 * C(d) * A

Where:
- F(drag) is the drag force in pounds (lbs)
- p is the air density in slug/ft^3
- v is the velocity in feet per second (ft/sec)
- C(d) is the coefficient of drag
- A is the area of the Challenger front end in square feet (ft^2)

To convert the drag force to power (P), we can use the formula:

P = F(drag) * v

Finally, we can convert the power to horsepower by dividing P by 550 ft*lbf/sec (the conversion factor for horsepower).

Now let's plug in the given values:

p = 0.0019 slug/ft^3
v = 587 ft/sec
C(d) = 0.398
A = 26.72 ft^2

First, let's calculate the drag force:

F(drag) = 1/2 * 0.0019 * 587^2 * 0.398 * 26.72
F(drag) ≈ 313.49 lbs

Next, let's calculate the power:

P = 313.49 * 587
P ≈ 184,130.63 ft*lbf/sec

Finally, let's convert the power to horsepower:

HP = 184,130.63 / 550
HP ≈ 334.78 HP

Therefore, Goldberg would need approximately 334.78 horsepower to reach 400 mph while delivering presents at an altitude of 5,813.6 ft.

390

1706

5,813 HP