write an equation in slope-intercept form of the line that passes through the given point (4,2) and is PARALLEL to the graph of the given equation. (x= -3)
y=2
y=2x+4
y=4x
x=4
i've been working on this problem for a bit and i genuinely don't know how to solve it. any help would be appreciated :)
right so would it be x=4?
ohh thank you reiny for the explanation. that helps a lot.
To find the equation of a line parallel to a given line, we need to determine the slope of the given line first.
From the given equation, x = -3, we notice that this is a vertical line parallel to the y-axis. The slope of a vertical line is undefined since it does not change in the x-direction.
So, in order for the line we're looking for to be parallel to x = -3, it also needs to be a vertical line.
Now, let's write the equation in slope-intercept form, y = mx + b.
Since the line is vertical, it means that x does not change, so we cannot have x as a variable on the right-hand side of the equation.
However, we know that a vertical line passing through the point (4,2) will always have x = 4. Therefore, the equation of the line is:
x = 4
This is the equation in slope-intercept form for a vertical line that is parallel to x = -3 and passes through the point (4,2).
I hope this helps! Let me know if you have any further questions.
parallel means that it has the same format as the given equation
just a different number
Any vertical line has the form x = c, where c is a constant and c is the x value of any point on the vertical line
Any horizontal line has the form y = k, where k is a constant and k is the y value of any point on the horizontal line
Your given equation is x= -3 , thus a vertical line
Now look at your x value of the given point.