Given this equation, 2Al + 3CuCl2 * 2H2O → 3Cu + 2AlCl3 + 6H2O

How do I calculate the theoretical yield of copper with the mass of Copper II chloride dihydrate as 2.40g and the mass of Copper as 1.40g?

Then the percentage yield?

convert those masses to moles.

You will need 3 moles of CrCl2 for every 2 moles of Al.
So, which will get used up first?
You will get the same moles of pure Cu as the number of moles of CuCl2 that were used.

oops--oobleck meant CuCl2 instead of CrCl2 but that should be obvious. Post your work if you get stuck and need more help.

To calculate the theoretical yield of copper (Cu) in this reaction, you need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed, determining the maximum amount of product that can be formed.

In this case, we have 2.40g of copper (II) chloride dihydrate (CuCl2 * 2H2O) and 1.40g of copper (Cu).

Step 1: Convert the given masses to moles.
The molar mass of CuCl2 * 2H2O = 170.5 g/mol
The molar mass of Cu = 63.55 g/mol

The number of moles of CuCl2 * 2H2O = 2.40g / 170.5 g/mol
The number of moles of Cu = 1.40g / 63.55 g/mol

Step 2: Determine the mole ratio between CuCl2 * 2H2O and Cu.
From the balanced chemical equation, the mole ratio is 3:2.

Step 3: Calculate the number of moles of Cu.
Multiply the number of moles of CuCl2 * 2H2O by the mole ratio to find the number of moles of Cu.
Number of moles of Cu = (2.40g / 170.5 g/mol) * (2 mol Cu / 3 mol CuCl2 * 2H2O)

Step 4: Calculate the mass of Cu from the number of moles.
Mass of Cu = Number of moles of Cu * Molar mass of Cu
Mass of Cu = (2.40g / 170.5 g/mol) * (2 mol Cu / 3 mol CuCl2 * 2H2O) * 63.55 g/mol

This will give you the theoretical yield of copper in grams.

To calculate the percentage yield, you need to compare the actual yield (1.40g) to the theoretical yield and calculate the percentage.

Percentage yield = (actual yield / theoretical yield) * 100%
Percentage yield = (1.40g / theoretical yield) * 100%

To calculate the theoretical yield of copper (Cu) and the percentage yield, you need to follow these steps:

Step 1: Determine the balanced chemical equation.
The given equation is already balanced: 2Al + 3CuCl2 * 2H2O → 3Cu + 2AlCl3 + 6H2O

Step 2: Determine the molar masses.
- Molar mass of CuCl2 * 2H2O:
Cu: 63.55 g/mol (copper atomic mass)
Cl: 2 * 35.45 g/mol (chlorine atomic mass)
H: 2 * 1.01 g/mol (hydrogen atomic mass)
O: 2 * 16.00 g/mol (oxygen atomic mass)
Adding them up: 63.55 + (2 * 35.45) + (2 * (2 * 1.01)) + (2 * (16.00)) = 170.46 g/mol

Step 3: Calculate the moles of Copper II chloride dihydrate (CuCl2 * 2H2O).
- Moles of CuCl2 * 2H2O = mass / molar mass
- Moles of CuCl2 * 2H2O = 2.40 g / 170.46 g/mol = 0.0141 mol

Step 4: Determine the mole-to-mole ratio between CuCl2 * 2H2O and Cu.
From the balanced equation, the mole-to-mole ratio of CuCl2 * 2H2O to Cu is 3:3, or 1:1.

Step 5: Calculate the moles of Copper (Cu).
Since the mole-to-mole ratio is 1:1, the moles of Cu produced will be the same as the moles of CuCl2 * 2H2O: 0.0141 mol.

Step 6: Calculate the theoretical yield of Copper (Cu).
- Theoretical yield of Cu = moles of Cu * molar mass of Cu
- Theoretical yield of Cu = 0.0141 mol * 63.55 g/mol = 0.894 g

Therefore, the theoretical yield of copper is 0.894 grams.

Step 7: Calculate the percentage yield.
- Percentage yield = (actual yield / theoretical yield) * 100
- Percentage yield = (1.40 g / 0.894 g) * 100 = 156.22%

Therefore, the percentage yield is 156.22%.