calculate the percentage by mass of all component in sodium trioxonitrate 4NaNo3(Na23 N14,o16
Note the sodium trioxonitrate is not an IUPAC approved name for NaNO3.
%Na = (atomic mass Na/molar mass NaNO3)*100 = ?
%N = (mass N/molar mass NaNO3)*100 = ?
etc.
BTW, drop the 4 in front of NaNO3.
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To calculate the percentage by mass of each component in sodium trioxonitrate (4NaNO3), you need to know the molar masses of each element present in the compound.
The molar mass of sodium (Na) is 23 g/mol.
The molar mass of nitrogen (N) is 14 g/mol.
The molar mass of oxygen (O) is 16 g/mol.
First, let's calculate the molar mass of sodium trioxonitrate (NaNO3):
4NaNO3 = (4 Na) + (1 N) + (12 O) = (4 x 23 g/mol) + (14 g/mol) + (12 x 16 g/mol) = 85 g/mol + 14 g/mol + 192 g/mol = 291 g/mol.
Next, we can calculate the percentage by mass of each component in NaNO3:
Percentage of Na = (Mass of Na / Molar mass of NaNO3) x 100%
= (4 x 23 g / 291 g) x 100% = (92 g / 291 g) x 100% ≈ 31.63%
Percentage of N = (Mass of N / Molar mass of NaNO3) x 100%
= (14 g / 291 g) x 100% ≈ 4.81%
Percentage of O = (Mass of O / Molar mass of NaNO3) x 100%
= (48 g / 291 g) x 100% ≈ 16.49%
Therefore, the percentage by mass of each component in sodium trioxonitrate (4NaNO3) is approximately:
Na ≈ 31.63%
N ≈ 4.81%
O ≈ 16.49%