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A solution is prepared by dissolving 4.9g of sucrose in 17g water. Calculate the boiling point, freezing point and osmotic pressure of this solution at 25 degree Celsius.

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humphrey

  1. mols sucrose = grams/molar mass = 4.9/342 = ?
    m = molality = mols sucrose/kg solvent = ?mols sucrose/0.017 kg = ?
    dT = Kf*m. You have Kf for water and molality from above. Solve for delta T then normal freezing point - delta T = new freezing point. Kf is 1.86 for water.

    dT = Kb*m
    You have Kb for water (0.512), m from above, solve for delta T. Then normal boiling point for H2O + delta T = new boiling point.

    osmotic pressure = MRT
    You know T (remember to use kelvin), and R (universal gas constant). Convert molality (m) to molarity (M) and solve for osmotic pressure. For very dilute solutions m may be used interchangeably with M
    Post your work if you get stuck.

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    DrBob222

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