The product of 2 numbers is 24,and the sum of their squares are 52.Find their sum.
do the math.
xy = 24
x^2 + y^2 = 52
Now, one way to find their sum is to recall that
(x+y)^2 = x^2 + y^2 + 2xy
So,
(x+y)^2 = 52 + 2*24
And you want (x+y), so ...
Thank u sir.
6 + 4 = ?
To solve this problem, we can start by assuming the two numbers are x and y.
Given that the product of the two numbers is 24, we can write the equation as:
x * y = 24 -- equation (1)
We are also given that the sum of their squares is 52. Mathematically, this can be written as:
x^2 + y^2 = 52 -- equation (2)
Now we have a system of two equations (equation 1 and equation 2) with two variables (x and y). We can solve this system of equations using substitution or elimination method.
Let's try substitution method:
From equation (1), we can express y in terms of x:
y = 24 / x
Substituting this value of y in equation (2):
x^2 + (24 / x)^2 = 52
Simplifying the equation:
x^2 + 576 / x^2 = 52
To get rid of the fractions, we can multiply both sides of the equation by x^2:
x^2 * x^2 + 576 = 52 * x^2
Expanding the equation:
x^4 + 576 = 52x^2
Rearranging the terms to form a quadratic equation:
x^4 - 52x^2 + 576 = 0
Now we have a quadratic equation in terms of x. We can solve this equation by factoring, completing the square, or using the quadratic formula. Once we find the values of x, we can substitute them back into equation (1) to find the corresponding values of y.
After finding the values of x and y, we can calculate their sum by adding them together: x + y = sum.