i want to prepare 1N of HCl in 100ml,our stock concentration is 32%.
32% what? by volume or by mass. That is w/v or w/w(m/m) I will assume w/v so 32% w/v is 32 g HCl/100 mL of solution or 320 g HCl/L solution..
What do you need for 1N HCl? That's 36.5 g HCl/L solution
1000 mL x (36.5/320) = 114 mL for 1L or 11.4 mL for 100 mL of solution.
Place 11.4mL of the 32% w/v solution in a 100 mL volumetric flask, make to the mark with distilled water, stopper, mix thoroughly, label.
Done.
You may like this way better.
You have 32 g HCl/100 mL. You want 36.5 g HCl/1000 mL or 3.65 g/100 mL.
Dilution formula is g1 x mL1 = g2 x mL2
32 x mL = 3.65 x 100
mL = 3.65*100/32 = 11.4 mL of the 32% stuff.
To prepare 1N of HCl in 100ml, you first need to determine the amount of concentrated HCl solution (stock solution) required to achieve the desired concentration.
Here are the steps to calculate the volume of the stock solution needed:
1. Convert the desired concentration from N (normality) to molarity (M). The conversion factor for HCl is 1N = 1M.
1N HCl = 1M HCl
2. Determine the amount of HCl required in moles. The formula to calculate moles is:
Moles = Molarity × Volume (in liters)
Since we want to prepare 100ml (0.1L) of the solution, the number of moles can be calculated as follows:
Moles = 1M × 0.1L = 0.1 moles
3. Calculate the volume of the stock solution required using the stock solution's concentration and the number of moles obtained in the previous step.
Let's assume the stock solution is 32% HCl by mass. This means that 32g of HCl is present in every 100g of the solution.
To determine the volume, you need to know the density of the stock solution. For this example, let's assume the density of the stock solution is 1.1 g/ml.
First, convert the mass of HCl required to grams:
Mass of HCl = Moles × Molar mass of HCl
The molar mass of HCl is approximately 36.5 g/mol. Thus,
Mass of HCl = 0.1 moles × 36.5 g/mol = 3.65 grams
Since the stock solution is 32% HCl, the mass of the stock solution required can be calculated as follows:
Mass of stock solution = Mass of HCl / (Percentage of HCl / 100)
Mass of stock solution = 3.65g / (32 / 100) = 11.40625g
Next, find the volume of the stock solution required by dividing the mass by the density of the stock solution:
Volume of stock solution = Mass of stock solution / Density of stock solution
Volume of stock solution = 11.40625g / 1.1 g/ml ≈ 10.37 ml
Therefore, to prepare 1N of HCl in 100ml, you need to measure approximately 10.37 ml of the 32% HCl stock solution and then dilute it to 100ml using distilled water.