How many total atoms in (NH4)2cro4
Oh, you're throwing some chemistry at me! Alright, let me channel my inner scientist to calculate that for you.
Okay, let's break it down. We have (NH4)2CrO4.
First off, let's deal with the ammonium ion, NH4+. It consists of one nitrogen atom and four hydrogen atoms.
Next up, we have the chromate ion, CrO4^2-. It has one chromium atom and four oxygen atoms.
Now, multiply each of their subscripts by the respective number of ions.
For NH4+: 1 nitrogen atom × 2 ions = 2 nitrogen atoms, and 4 hydrogen atoms × 2 ions = 8 hydrogen atoms.
For CrO4^2-: 1 chromium atom × 1 ion = 1 chromium atom, and 4 oxygen atoms × 1 ion = 4 oxygen atoms.
Adding them all up, we have 2 nitrogen atoms, 8 hydrogen atoms, 1 chromium atom, and 4 oxygen atoms.
In total, (NH4)2CrO4 contains 2 + 8 + 1 + 4 = 15 atoms.
So, we've got 15 atoms clowning around in (NH4)2CrO4! Hope that helps!
To calculate the total number of atoms in a chemical compound, you need to consider the number of each type of atom present and any subscripts or coefficients. Let's calculate the total number of atoms in (NH4)2CrO4 step-by-step:
1. Break down the compound into its individual elements:
(NH4)2CrO4 consists of the following elements: N (Nitrogen), H (Hydrogen), Cr (Chromium), and O (Oxygen).
2. Determine the number of each type of atom in the compound:
- (NH4)2: The parentheses and the 2 subscript outside mean that the entire NH4 group is repeated twice.
- NH4 consists of N and four H atoms.
- Therefore, there are 1 N atom and 4 H atoms in each NH4 group.
- Since the NH4 group is repeated twice, we have 2 NH4 groups.
- So, there are 2 N atoms and (2 * 4) = 8 H atoms.
- Cr: There is 1 Cr atom present in the compound.
- O4: The subscript 4 means that there are four O atoms present.
3. Calculate the total number of atoms:
- Add up the number of atoms for each element:
- N: 2 atoms (2 N atoms in 2 NH4 groups)
- H: 8 atoms (4 H atoms in 2 NH4 groups)
- Cr: 1 atom
- O: 4 atoms
Therefore, (NH4)2CrO4 contains a total of 2 + 8 + 1 + 4 = 15 atoms.
To determine the number of total atoms in (NH4)2CrO4, you need to count the atoms of each element and then multiply the count by their respective subscripts.
Let's break down the chemical formula:
(NH4)2CrO4
In the formula, (NH4) represents the ammonium ion, and CrO4 represents the chromate ion.
Atoms in ammonium ion (NH4):
- 1 nitrogen atom (N)
- 4 hydrogen atoms (H)
Atoms in chromate ion (CrO4):
- 1 chromium atom (Cr)
- 4 oxygen atoms (O)
Now, let's count the total number of atoms:
Ammonium ion:
- 1 nitrogen atom × 2 subscripts = 2 nitrogen atoms (N)
- 4 hydrogen atoms × 2 subscripts = 8 hydrogen atoms (H)
Chromate ion:
- 1 chromium atom (Cr)
- 4 oxygen atoms (O)
Therefore, the total number of atoms in (NH4)2CrO4 is:
2 nitrogen atoms (N) + 8 hydrogen atoms (H) + 1 chromium atom (Cr) + 4 oxygen atoms (O) = 15 atoms in total.