At what time is the missile 72m above ground level?
42 seconds
How can you know that without the speed of the missle?
To determine the time when the missile is at a certain height, we need additional information such as the initial velocity, angle of projection, and acceleration of the missile. Without these details, we cannot accurately calculate the exact time when the missile is at 72m above the ground level.
However, if we assume that the missile follows a projectile motion with no air resistance, we can use basic equations of motion to estimate the time it takes for the missile to reach a certain height. Let's assume the missile is launched from the ground level (h = 0m).
The height of an object in projectile motion can be calculated using the equation:
h = h0 + (v0y * t) - (1/2 * g * t^2)
where:
- h is the height above the ground level,
- h0 is the initial height (h0 = 0m, as the missile is launched from the ground level),
- v0y is the vertical component of the initial velocity,
- t is the time elapsed, and
- g is the acceleration due to gravity (approximately 9.8 m/s^2).
Since we are given the height of 72m above the ground level, we can rearrange the equation to solve for the time (t):
72m = 0m + (v0y * t) - (1/2 * 9.8 m/s^2 * t^2)
Simplifying the equation, we get:
4.9 t^2 - v0y t - 72 = 0
This equation is a quadratic equation, and by solving it using the quadratic formula, we can find the time (t) when the missile is at a height of 72m above the ground level.
Again, please note that without more specific information about the missile's initial velocity, angle of projection, and acceleration, we cannot provide an exact time when the missile reaches the specified height.