Six times the sum of a number and 16 is at most 27.
Use the variable y for the unknown number.
To solve this problem, we can start by translating the given information into an equation.
The sum of a number (y) and 16 can be represented as y + 16.
Six times this sum can be written as 6(y + 16).
The word "is" in this context can be translated as an equals sign (=).
Finally, "at most" indicates that the equation satisfies an inequality symbol (≤).
Putting it all together, the equation becomes:
6(y + 16) ≤ 27.
To find the value of y that satisfies this inequality, we need to isolate y by solving the equation step by step.
First, distribute 6 to y and 16:
6y + 96 ≤ 27.
Next, subtract 96 from both sides to isolate the variable term:
6y ≤ 27 - 96.
Simplifying the right side gives:
6y ≤ -69.
Finally, divide both sides of the inequality by 6 to solve for y:
y ≤ -69/6.
This can be simplified as:
y ≤ -11.5.
Therefore, the unknown number (y) is less than or equal to -11.5.