Indicate the concentration of each ion present in the solution formed by mixing the following.

44.0 mL of 0.110 M Na2SO4 and 25.0 mL of 0.200 M KCl. Assume that the volumes are additive.

Enter your answers, separated by commas, using three significant figures.

Please Help Me.

Oh, I'm always here to help, even if it means clowning around with chemistry! Let's mix these solutions and find out the concentration of each ion.

First, let's find the number of moles of sodium sulfate (Na2SO4) in the solution.

Number of moles of Na2SO4 = concentration (M) x volume (L) = 0.110 M x 0.0440 L = 0.00484 moles.

Similarly, let's find the number of moles of potassium chloride (KCl) in the solution.

Number of moles of KCl = concentration (M) x volume (L) = 0.200 M x 0.0250 L = 0.00500 moles.

Since the volumes are additive, the total volume of the solution is 44.0 mL + 25.0 mL = 69.0 mL = 0.0690 L.

Now, let's calculate the concentration of each ion.

Concentration of Na+ = moles of Na+ / total volume of solution
= 2 x moles of Na2SO4 / total volume of solution
= 2 x 0.00484 moles / 0.0690 L
= 0.280 M (approximately)

Concentration of K+ = moles of K+ / total volume of solution
= moles of KCl / total volume of solution
= 0.00500 moles / 0.0690 L
= 0.0725 M (approximately)

Concentration of SO4^2- = moles of SO4^2- / total volume of solution
= moles of Na2SO4 / total volume of solution
= 0.00484 moles / 0.0690 L
= 0.0702 M (approximately)

There we have it! The concentration of Na+ is 0.280 M, the concentration of K+ is 0.0725 M, and the concentration of SO4^2- is 0.0702 M. Hope that helps, and remember, chemistry can always use a bit of clowning around!

To find the concentration of each ion present in the solution, we need to calculate the moles of each ion in each solution and then combine them.

Let's start with Na2SO4:
Molarity (M) = moles (mol) / volume (L)

Moles (Na2SO4) = Molarity (Na2SO4) x Volume (Na2SO4)
= 0.110 M x 0.0440 L
= 0.00484 mol Na2SO4

Since Na2SO4 dissociates into 2 Na+ ions and 1 SO4^2- ions, the number of moles of Na+ and SO4^2- will be:

Moles (Na+) = 2 x Moles (Na2SO4)
= 2 x 0.00484 mol
= 0.00969 mol Na+

Moles (SO4^2-) = 1 x Moles (Na2SO4)
= 1 x 0.00484 mol
= 0.00484 mol SO4^2-

Now, let's calculate the moles of KCl:
Moles (KCl) = Molarity (KCl) x Volume (KCl)
= 0.200 M x 0.0250 L
= 0.00500 mol KCl

Since KCl dissociates into 1 K+ ion and 1 Cl- ion, the number of moles of K+ and Cl- will be:

Moles (K+) = 1 x Moles (KCl)
= 1 x 0.00500 mol
= 0.00500 mol K+

Moles (Cl-) = 1 x Moles (KCl)
= 1 x 0.00500 mol
= 0.00500 mol Cl-

Now, we can calculate the concentration of each ion by dividing the moles of each ion by the total volume of the solution (44.0 mL + 25.0 mL = 69.0 mL = 0.0690 L).

Concentration (Na+) = Moles (Na+) / Total volume
= 0.00969 mol / 0.0690 L
= 0.140 M Na+

Concentration (SO4^2-) = Moles (SO4^2-) / Total volume
= 0.00484 mol / 0.0690 L
= 0.0702 M SO4^2-

Concentration (K+) = Moles (K+) / Total volume
= 0.00500 mol / 0.0690 L
= 0.0725 M K+

Concentration (Cl-) = Moles (Cl-) / Total volume
= 0.00500 mol / 0.0690 L
= 0.0725 M Cl-

So, the concentration of each ion in the solution formed by mixing the given solutions is:
0.140 M Na+, 0.0702 M SO4^2-, 0.0725 M K+, 0.0725 M Cl-.

To find the concentration of each ion present in the solution, you need to determine the number of moles of each ion in the solution.

Let's start with Na2SO4:
1. Calculate the number of moles of Na2SO4 in the first solution:
Moles of Na2SO4 = concentration (M) x volume (L)
Moles of Na2SO4 = 0.110 M x 0.0440 L

2. Since Na2SO4 dissociates into 2 Na+ ions and 1 SO4^2- ion, the total number of moles of ions (Na+ and SO4^2-) is multiplied by 3:
Moles of ions = 3 x (0.110 M x 0.0440 L)

Now, let's move on to KCl:
1. Calculate the number of moles of KCl in the second solution:
Moles of KCl = concentration (M) x volume (L)
Moles of KCl = 0.200 M x 0.0250 L

2. Since KCl dissociates into 1 K+ ion and 1 Cl- ion, the total number of moles of ions is:
Moles of ions = 2 x (0.200 M x 0.0250 L)

By adding the moles of ions from both solutions, you will obtain the total number of moles of each ion in the solution.

Once you have the total number of moles of each ion, you can calculate the concentration (in M) of each ion by dividing by the total volume (in L) of the solution, which is the sum of the volumes used in the mixing (44.0 mL + 25.0 mL).

Finally, remember to round your answers to three significant figures and separate them with commas.

44.0 mL of 0.110 M Na2SO4 and 25.0 mL of 0.200 M KCl.

For [SO4]^2- = 0.110 M x [44.0/(44.0+25.0)] = ?
For Na^+ it is twice that since there are 2 Na^+ for every Na2SO4.
For K^+ and Cl^- = 0.200 x [25.0/(44.0+25.0)] = ?