A body of mass 4.2kg moving with a velocity of 10m/s due east,hit a stationary body of mass 2.8kg.if they stick together after collision and move with a velocity v due east calculate the value of v
stick together: only law of conservation of momentum applies
4.2*10E+2.8*OE= (4.2+2.8)V
V= 42/(7.0) East
M1U=(m1+m2)v
=4.2*10=(4.2+2.8)v
v=4.2×10/7
v=6m/s
Well, it seems like we've got some physics on our hands! *insert clown whistle*
To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum before a collision is equal to the total momentum after the collision.
The initial momentum is calculated by multiplying the mass of the first body by its velocity:
Initial momentum = (Mass1 × Velocity1) = (4.2 kg × 10 m/s) = 42 kg·m/s (due east)
Similarly, the initial momentum of the second body is zero because it is stationary.
After the collision, the two bodies stick together and move as one, so their final momentum is the same:
Final momentum = (Total mass × Final velocity) = ((4.2 kg + 2.8 kg) × v) = 7 kg × v (due east)
According to the conservation of momentum, the initial momentum and final momentum must be equal:
Initial momentum = Final momentum
So, we have:
42 kg·m/s = 7 kg × v
To find the value of v:
v = 42 kg·m/s ÷ 7 kg
v = 6 m/s
Therefore, the value of v is 6 m/s, both in magnitude and direction! Voilà! *throws confetti*
M1 = 4.2kg, V1 = 10 m/s.
M2 = 2.8kg, V2 = 0.
Momentum before = Momentum after
M1*V1 + M2*V2 = M1V + M2*V.
4.2*10 + 2.8*0 = 4.2*V + 2.8*V,
V =
To calculate the value of the final velocity (v) of the two bodies after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.
The momentum of an object is given by the product of its mass and velocity. Therefore, the momentum (P) of an object can be calculated using the equation:
P = m * v
Where:
P = Momentum
m = Mass of the object
v = Velocity of the object
Let's assign variables for the given information:
Mass of the first body (m1) = 4.2 kg
Velocity of the first body (v1) = 10 m/s
Mass of the second body (m2) = 2.8 kg
Final velocity of the two bodies after collision (v) = ?
Since the two bodies stick together after collision, their combined mass (m1 + m2) will be moving with the final velocity (v). So, we can write the equation based on the conservation of momentum:
Total momentum before collision = Total momentum after collision
(m1 * v1) + (m2 * 0) = (m1 + m2) * v
Now, let's substitute the given values into the equation:
(4.2 kg * 10 m/s) + (2.8 kg * 0) = (4.2 kg + 2.8 kg) * v
42 kg⋅m/s + 0 kg⋅m/s = 7 kg * v
42 kg⋅m/s = 7 kg * v
To isolate the final velocity (v), we need to divide both sides of the equation by 7 kg:
v = (42 kg⋅m/s) / 7 kg
v = 6 m/s
Therefore, the value of v, representing the final velocity of the two bodies after the collision, is 6 m/s due east.