Let z be the standard normal variable. Find z if z satisfies p(Z<z)=.2090. Is that just -0.8?
To find the value of z that satisfies the probability p(Z < z) = 0.2090, we need to use a standard normal distribution table or a calculator that provides the cumulative distribution function (CDF) for the standard normal distribution.
The CDF gives us the probability of the standard normal random variable Z being less than or equal to a given value. In this case, we have p(Z < z).
By looking up the probability 0.2090 in a standard normal distribution table or using a calculator, we find that the corresponding z-value is approximately -0.8064 (rounded to four decimal places).
Therefore, z ≈ -0.8064, not -0.8.