Determine the slope and y-intercept for the line that passes through the points (5, 5) and (−5, 1). Show your work.
I found the slope its 2/5, but i don't know how to find the y-intercept. Can someone explain how to find the y-intercept please?
since the y-intercept is the value of b when the equation is in the form
y = mx + b
from CodyJinks' line
5=(2/5)5 + b , all we need to do is find b
5 = 2 + b
b = 3
Would the y-intercept be 3?
You would graph the line with the found slope and plot it through the points and see where it crosses the axis.
Better yet use a point ex) 5=(2/5)5 + b
Following the form of y=mx+b
this really did not help me sorry but are you trying to say the answer is 3
To find the y-intercept of a line, you need the equation of the line in either slope-intercept form or standard form. Since you've already found the slope, we can use the point-slope form of a linear equation to find the equation of the line passing through the points (5, 5) and (-5, 1).
The point-slope form of a linear equation is:
y - y1 = m(x - x1)
where m represents the slope of the line and (x1, y1) represents a point on the line.
Let's use the point (5, 5) to find the equation of the line:
y - 5 = (2/5)(x - 5)
Now, simplify and rearrange the equation to get it in slope-intercept form (y = mx + b), where 'b' represents the y-intercept:
y - 5 = (2/5)x - 2
y = (2/5)x + 3
From this equation, we can see that the y-intercept is 3. So the line that passes through the points (5, 5) and (-5, 1) has a slope of 2/5 and a y-intercept of 3.
To summarize:
Slope = 2/5
Y-intercept = 3