Login or Sign Up

Ask a New Question

how do i get the degree for (tan+1)(tanx-2)=0 in the interval of 0 is less that or equal to x and x is less then or equal to 360

The angles are arctan -1 and arctan 2. There are four such angles in that interval

Similar Questions

Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to

Top answer: To solve this problem, we can start by simplifying the expression (1+tanx)/(1-tanx) using the Read more.
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to

Top answer: From: a(1-tanx)=b(1+tanx) multiply both sides by cos(x) to get a(cos(x)-sin(x))=b(cos(x)+sin(x)) Now Read more.
Find the smallest positive value of x(in degree) for which tan(x+100°)=tan(x+50°)*tanx*tan(x-50°)

Top answer: Try an approximate graphical solution and refine solution by iterations. Here's a graphical solution Read more.
Perform the addition or subtraction.tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the

Top answer: from you second line tan^2(x)/tan(x) - sec^2x/tanx = (tan^2 x - sec^2 x)/tanx = (tan^2 x - (1 + Read more.
If limit as delta x approaches 0 of tan(0+Δx)-tan(0)/Δx =1which of the following is false: d/dx [tanx]=1 the slope of y =

Top answer: assuming those 0's should be x's the first assertion is false. d/dx(tanx) = 1 at x=0, not Read more.
Hello im trying to integrate tan^3 dxi have solved out the whole thing but it doesnt match up with the solution.. this is what i

Top answer: Break it into two integrals, integral (sec^2(x)tan(x))dx and integral(-tan(x))dx. Both can be solved Read more.
Hello im trying to integrate tan^3 dxi have solved out the whole thing but it doesnt match up with the solution.. this is what i

Top answer: (on the 17th line it shud be u^2/u) Read more.
solve the first equation in each pair of equations or y and /or z. Then use the same strategy to solve the second equation for x

Top answer: y^2 = 1/3 y = ± 1/√3 so tan^2 x = 1/3 tanx = ± 1/√3 so x could be in all 4 quadrants knowing Read more.
How do I solve this?tan^2x= 2tanxsinx My work so far: tan^2x - 2tanxsinx=0 tanx(tanx - 2sinx)=0 Then the solutions are: TanX=0

Top answer: tan(arccos 1/2) = sqrt3/2 and tan(arctan 0) = 0 So, the solutions are: x=arctan 0 and x=arccos 1/2 Read more.
Identify tanX as a fraction and as a decimal rounded to the nearest hundredth.A. tan X = 6.4/9.6 ≈ 0.67 B. tan X = 7.2/9.6 ≈

Top answer: Seeing as no one here knows how to answer this and are being very rude about it. The correct answer Read more.