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The fastest recorded pitch in major-league baseball, thrown by Nolan Ryan in 1974, was clocked at 100.8 mi/h. If a pitch were thrown horizontally with this velocity, how far would the ball fall vertically by the time it reached home plate, 60.0 ft away?

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Ellie

  1. u = 162.3 km/h = 45.083 m/s
    x = xo + u*t + 1/2 at^2
    45.083*t + 0 = 18.3
    t = 0.406 s
    y = yo + u*t + 1/2 at^2
    y + 0 - 4.9t^2 = 0
    y = 4.9(0.406)^2
    y = .808 m

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    Lol Someone

  2. Easier explained,
    Velocity = (162,300/ 3600s in 1 hr) = 45.08m/sec.
    Time to travel 18.3m = (d/v), = 18.3/45.08) = .406 secs.
    Height of fall in .406s. = 1/2 (t^2 x g), = .808m.

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    Lol Someone

  4. the question was in English units ... not metric ... 2.64 ft

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    R_Scott

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