algebra

Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?

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  1. slope JK = (3+5)/(-6+4) = 8/-2 = -4

    so you have
    y = -4x + b

    plug in either point and solve for b

    What did you get ?

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    Reiny

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