Physics

a cannon tilted up at 33 degree angle fires a cannon ball at 88 m/s from atop a 12.0 m high fortress wall. What’s the balls impact speed on the ground?

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asked by J
  1. the height of the ball is
    h(t) = 12 + (88 sin33°)t - 4.9t^2
    h=0 at t=10
    v(t) = 88 sin33° - 9.8t
    so plug and chug

    alternatively, consider the ball as being thrown down with an initial speed of
    -88 sin33° m/s
    and find how long it takes to drop 12m.
    Plug that into the v(t) equation

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