Please help. I have something from my algebra 1 class:
For the equation ax+c+bx+d, where a is not equal to b and c is not equal to d. What is x?
I know you're supposed to solve for x but I don't know how?
I suspect a typo. Surely you meant
ax+c = bx+d
So, collect all the x stuff on the left, to get
ax-bx = d-c
x(a-b) = d-c
x = (d-c)/(a-b)
Thank You!
To solve for x in the equation ax+c+bx+d, you need to combine like terms and isolate the x term on one side of the equation. Here's how you can do it step by step:
Step 1: Combine like terms
Combine the x terms (ax + bx) and the constant terms (c + d) to simplify the expression. This gives us:
(ax + bx) + (c + d) = 0
Step 2: Group x terms and constant terms separately
Rewrite the equation to separate the x terms and the constant terms:
ax + bx + c + d = 0
Step 3: Factor out x from the x terms
Factor out x from the x terms (ax and bx):
x(a + b) + c + d = 0
Step 4: Solve for x
To isolate x, we need to eliminate the constant terms. Subtract (c + d) from both sides of the equation:
x(a + b) = - (c + d)
Step 5: Divide by (a + b)
Divide both sides of the equation by (a + b) to solve for x:
x = - (c + d) / (a + b)
And that's how you solve for x in the given equation ax+c+bx+d.