PHYSICS FINE THE WORK DONE AGAINST THE GRAVITY?
your question makes zero sense.
A BOY OF MASS 50KG RANS UP A SET OF STEPS TOTAL HEIGHT 3.0M.FINE THE WORK DONE AGAINST GRAVITY?
what is mass*g*height? Answer: 50*9.8*3.0 joules
To find the work done against gravity, you first need to understand the concept of work and gravitational force.
Work is defined as the product of the force acting on an object and the displacement of the object in the direction of the force. Mathematically, it is given by the equation:
Work = Force × Displacement × cos(θ)
Where:
- Work is the amount of energy transferred to or from an object.
- Force is the amount of push or pull acting on the object.
- Displacement is the distance moved by the object.
- θ (theta) is the angle between the force vector and the displacement vector.
In the case of work done against gravity, the force involved is the gravitational force acting on the object, which can be calculated using the equation:
Force = mass × acceleration due to gravity
The acceleration due to gravity is a constant value of approximately 9.8 m/s² on the surface of the Earth.
Let's say you have an object of mass "m" that you lift vertically upwards by a distance "h." The force required to lift the object against gravity would be:
Force = mass × acceleration due to gravity
Force = m × 9.8
The displacement would be the vertical distance traveled, which is "h." Since the force and displacement are in the same direction when lifting an object vertically upwards, the angle θ between them is 0 degrees.
Now, you can calculate the work done against gravity using the work equation:
Work = Force × Displacement × cos(θ)
Work = (m × 9.8) × h × cos(0)
Work = m × 9.8 × h
So, the work done against gravity when lifting an object vertically upwards is given by the equation Work = m × 9.8 × h, where m is the mass of the object and h is the height or displacement.