the sum of ages of sarpong and quartey is 50 years in five years time quartey will be 4 times the age of sarpong now how old is each boy
s + q = 50
q+5 = 4s
Now just solve for s and q
Nathaniel
To solve this problem, let's assign variables to the ages of Sarpong and Quartey.
Let's say Sarpong's current age is X years.
And Quartey's current age is Y years.
According to the given information, the sum of their ages is 50 years:
X + Y = 50 ----------- Equation 1
In five years from now, Quartey will be 4 times the age of Sarpong:
(Y + 5) = 4(X) ----------- Equation 2
Now, we can solve these two equations simultaneously to find the values of X and Y.
First, rearrange Equation 2:
Y + 5 = 4X
Y = 4X - 5
Now substitute the value of Y from Equation 2 into Equation 1:
X + (4X - 5) = 50
5X - 5 = 50
5X = 55
X = 11
Substitute the value of X back into Equation 1 to find Y:
11 + Y = 50
Y = 50 - 11
Y = 39
So, Sarpong is currently 11 years old, and Quartey is currently 39 years old.