Write an equation in standard form using integers y=-2/3x-1

Sure, here's an equation in standard form:

2x + 3y = -6

To convert the equation y = -2/3x - 1 into standard form using integers, we need to eliminate the fraction and rearrange the terms.

First, let's eliminate the fraction. We can do this by multiplying the entire equation by the denominator (3) to get rid of the fractional coefficient (-2/3). Multiplying both sides of the equation by 3 gives us:

3y = (-2/3)(3x) - 3(1)

Simplifying, we have:

3y = -2x - 3

Next, let's rearrange the equation by moving the x-term to the other side. Adding 2x to both sides of the equation gives us:

2x + 3y = -3

Finally, to put the equation in standard form with integer coefficients, we arrange the terms in descending order of powers of x:

2x + 3y + 3 = 0

Therefore, the equation in standard form, using integers, is 2x + 3y + 3 = 0.

To write the equation in standard form using integers, we need to get rid of the fraction in the equation. We can do this by multiplying both sides of the equation by the least common multiple (LCM) of the denominators.

The equation is y = -2/3x - 1.

To eliminate the fraction, we need to multiply both sides of the equation by 3, which is the denominator of -2/3.

3 * y = 3 * (-2/3x) + 3 * (-1).

Simplifying the equation:

3y = -2x - 3.

Now, we want the x term to have a positive coefficient, so we can multiply through the equation by -1:

-1 * (3y) = -1 * (-2x - 3).

Simplifying further:

-3y = 2x + 3.

Finally, let's rearrange the equation into standard form, where the equation follows the form Ax + By = C:

2x + 3 + 3y = 0.

The equation in standard form, using integers, is 2x + 3y + 3 = 0.

first step: clear the fractions:

3y = -2x - 3

Now just rearrange the terms to standard form.