A town clock has a minute hand that is 1.5 meters long and an hour hand that is 1.2 meters long. What is the approximate distance in meters between the ends of the hands at 9 o'clock?

Question

A town clock has a minute hand that is 1.5 meters long and an hour hand that is 1.2 meters long. What is the approximate distance in meters between the ends of the hands at 9 o'clock?

2.3
1.9
0.9
0.3

can someone get me the answer? thanks

Answer 1

guys the equation is 1.5^2+1.2^2

whenever a number has "^2" after it that means you have to multiply the number by itself. So 1.5x1.5= 2.25 and 1.2^2= 1.44. Then next you have to add the answers. 2.25+1.44= 3.69. Then next what you wanna do is find the root of the number. To find the root you just find what 2 numbers multiplied equal your first number. For example. The root of 64 is 8 because 8x8= 64.
anyway. The root of 3.69 is 1.92093727 because 1.92093727x1.92093727=3.69
so now you just round the answer. So your answer is 1.9.
Hope this helped lol

Answer 2

Treat as a trig. problem. At 9 o clock you would have a triangle with a 90 degree angle so (1.5)^2 + (1.2)^2 = C^2 solve for C

Answer 3

It is also known as the Pythagorean theorem, which can be used for any right (90 degree) triangle.

Answer 4

THANKS SO MUCH

Answer 5

And how would that help the ppls who dont understand that stuff?

Answer 6

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Answer 7

ur welcome cool kid

Answer 8

1.9 it is sonny bit.

Answer 9

To find the distance between the ends of the hands at 9 o'clock, we can use the concept of trigonometry. The minute hand and the hour hand can be seen as the radius of a circle, with the pivot point as the center. At 9 o'clock, the minute hand points directly upwards, while the hour hand is pointing left.

The minute hand forms a right-angled triangle with the center and the endpoint. Using the Pythagorean theorem, we can find the length of the hypotenuse:

c^2 = a^2 + b^2

Since the minute hand is 1.5 meters long, the length of the hypotenuse is:

c = √(1.5^2 + 0^2)
≈ √2.25
≈ 1.5 meters

The hour hand also forms a right-angled triangle but with shorter sides. We can use the same formula:

c^2 = a^2 + b^2

Since the hour hand is 1.2 meters long, the length of the hypotenuse is:

c = √(1.2^2 + 0^2)
≈ √1.44
≈ 1.2 meters

Now, to find the distance between the ends of the hands, we subtract the length of the hour hand from the length of the minute hand:

Distance = 1.5 meters - 1.2 meters
= 0.3 meters

Therefore, the approximate distance in meters between the ends of the hands at 9 o'clock is 0.3 meters.