Good morning. This is a repost. The system is telling me my calculations is incorrect. I thought a fresh pair of eyes would help.
Suppose a monatomic ideal gas is contained within a vertical cylinder that is fitted with a movable piston. The piston is frictionless and has a negligible mass. The area of the piston is 3.06 10-2 m2, and the pressure outside the cylinder is 1.02 105 Pa. Heat (2109 J) is removed from the gas. Through what distance does the piston drop?
For Further Reading
Physics HELP!!!!!!!! - bobpursley, Tuesday, April 17, 2007 at 9:29am
PV=work
V= area *distance
You know P, area, and work. Solve for distance.
According to the formula provided
PV=work
P(area x distance)= work
solve for distance
distance = work - P/ area
this is where it get confusing for me
P= 1.02 x 10^5 Pa
A= 3.06 x 10^-2 m^2
W= ? I am unsure how to get he value of work
For Further Reading
Physics, still don't get it! - bobpursley, Wednesday, April 18, 2007 at 10:38pm
Work is heat, and heat is work. It was given.
Physics, still don't get it! - Mary, Wednesday, April 18, 2007 at 11:10pm
Please check my working out. The system is saying it is wrong.
PV = W
PV = 2109J
V = 2109J/ 1.02 X 10^5Pa
V = 0.020676471m^3
Area x distance = 0.020676471m^3
distance = 0.020676471/ 3.06 x 10^-2m^2
distance = 0.6757 m
Physics, still don't get it! - bobpursley, Wednesday, April 18, 2007 at 11:16pm
I don't see anything wrong.
Based on the information provided, it appears that you are attempting to find the distance through which the piston drops when heat is removed from the gas.
To solve for the distance, you need to use the equation PV = work, where P is the pressure, V is the volume, and work is the amount of work done on or by the gas. In this case, since the piston is moving, the work is done on the gas and is equal to the heat removed from the gas.
So, the equation becomes:
PV = work
Substituting the given values:
P = 1.02 x 10^5 Pa
A = 3.06 x 10^-2 m^2
W = 2109 J (given value of heat removed)
Now, we can solve for V using the equation PV = work:
V = W / P
V = 2109 J / (1.02 x 10^5 Pa)
V = 0.020676471 m^3
Next, since we want to find the distance through which the piston drops, we can use the formula V = A * distance, where A is the area of the piston and distance is the distance through which the piston drops.
Rearranging the formula to solve for distance:
distance = V / A
distance = 0.020676471 m^3 / (3.06 x 10^-2 m^2)
distance = 0.6757 m
Therefore, the distance through which the piston drops is approximately 0.6757 meters.
Based on the calculations provided, it appears that your solution is correct. If the system is still indicating that your solution is incorrect, it would be helpful to review the question and calculations to ensure there are no mistakes in units or calculations.