1.Sin((9*180)/2+thetA) =?
1. Sin theta 2.cos theta
Then 2.ABC er AD modhoma is 5 cm and BC is 8 cm so AB square and AC square =?
1.28 2.82 3.42 4.84
sin((9*180)/2 + θ)
= sin(9*90 + θ)
= sin(9*90)cosθ + cos(9*90)sinθ
= sin(720+90)cosθ + cos(720+90)sinθ
= cosθ
The rest of it makes no sense to me at all.