Im having trouble with this,
×+y=2 ; (8,5)
Can you please show me how to do it?
well, if x=8 and y=5, it is clear that x+y = 8+5 = 13, not 2
Do you want a line parallel to x+y=2, passing through (8,5)? In that case, since the slope of x+y=2 is -1, you want
y-5 = -1(x-8)
or some rearrangement of that.
Your question was very vague.
I have homework on perpendicular lines. Does that clear it up?
yes. Just modify what I told you. What is the slope of the line perpendicular to x+y = 2 ?
Use that in your point-slope form of the line you want.
I have to write it as an equation, Ill give you an example;
y=×-6 ; (-1,2)
m=-1
....
I have to write it like that.
Sure! It seems like you have an equation × + y = 2, and you want to find the value of × when y is equal to 5.
To do this, you need to substitute the value of y into the equation and solve for ×. Let's go step by step:
Step 1: Substitute the value of y into the equation.
Replace y with 5 in the equation:
× + 5 = 2
Step 2: Solve for ×.
To isolate ×, subtract 5 from both sides of the equation:
× = 2 - 5
Step 3: Simplify.
× = -3
So, when y is equal to 5, × is equal to -3.