a diver jumps off a cliff with an intial velocity of 5.0 m/s. the diver strikes the water 3.0s later. what is the vertical speed of the diver upon reaching the surface of the water?
wondering which direction did he jump? Vertically up, vertically down, or horizontal?
initial velocity up or down or horizontal ? (Note - Velocity vector has direction; speed does not. Speed needs speedometer. Velocity needs speedometer and compass.) I define v up and Vi is initial v up. Hi is height of cliff and h is height of diver above water, zero at splashdown.
v = Vi - g t
h = Hi +Vi t - 4.9 t^2
To find the vertical speed of the diver upon reaching the surface of the water, you can use the principle of linear motion and the equation for velocity.
The equation for velocity in linear motion is given by:
velocity (v) = initial velocity (u) + acceleration (a) * time (t)
In this case, the diver jumps off the cliff with an initial velocity of 5.0 m/s, and the acceleration due to gravity is acting in the downward direction, which we'll assume is -9.8 m/s².
Since the diver reaches the water after 3.0 seconds, we can substitute these values into the equation to find the final vertical velocity.
v = u + a * t
v = 5.0 m/s + (-9.8 m/s²) * 3.0 s
Now, let's calculate the vertical speed of the diver upon reaching the surface of the water.
v = 5.0 m/s + (-29.4 m/s)
v = -24.4 m/s
The negative sign indicates that the velocity is directed downward, which is expected since the diver is falling towards the water. Therefore, the vertical speed of the diver upon reaching the surface of the water is -24.4 m/s.