A group of people pay $720 for admission tickets to an amusement park. The price of an adult ticket is $15, and a child ticket is $8. There are 25 more adults than children. How many children are in the group?
Write Equations
x=number of adult tickets
y=number of child tickets
1. 720=15x+8y
2. x=y+25
Plug second equation into the first:
720=15(y+25)+8y
Solve for y:
720=15y+8y+375
720=23y+375
345=23y
15=y
So there are 15 children in the group.
X children.
x+25 adults.
8x + 15(x+25) = 720.
23x = 720-375,
X = 15.
Let's solve this problem step by step.
Let's assume the number of children in the group as "x".
Since there are 25 more adults than children, the number of adults can be represented as "x + 25".
The price of an adult ticket is $15, so the total cost contributed by adults would be (x + 25) * $15.
Similarly, the price of a child ticket is $8, so the total cost contributed by children would be x * $8.
According to the problem, the total cost paid by the group is $720.
So, the equation representing the total cost contributed by adults and children is:
(x + 25) * $15 + x * $8 = $720
Now, we can simplify this equation and solve for x:
15x + 375 + 8x = 720
23x + 375 = 720
23x = 720 - 375
23x = 345
x = 345 / 23
x ≈ 15
Therefore, there are approximately 15 children in the group.
To solve this problem, we can set up a system of equations based on the given information.
Let's assume that the number of children in the group is C. Since there are 25 more adults than children, the number of adults would be C + 25.
Now, we can write an equation to represent the total cost paid by the group: 8C + 15(C + 25) = 720.
Let's solve this equation step by step:
8C + 15(C + 25) = 720
First, distribute 15 to C and 25:
8C + 15C + 375 = 720
Combine like terms:
23C + 375 = 720
Subtract 375 from both sides:
23C = 720 - 375
23C = 345
Now, divide both sides of the equation by 23:
C = 345 / 23
C = 15
Therefore, there are 15 children in the group.